1. Construct a truth table for an active-LOW output BCD (1-of-10) decoder. 2. Pe

Question

1. Construct a truth table for an active-LOW output BCD (1-of-10) decoder.

2.      Perform the following computation using 2

For the multiplexer shown below, determine die output for the following inpit state: DO = 0,D1 = 1, D2 = 1, D3 = 0, S0 = 1, SI = 0. Will the following circuit function properly as a half-adder? You may wish to fill out a truth table to compare it to that of the half-adder. Derive the truth table for the Y output in the diagram below. A 7-segment decoder/driver drives the dispaly below. using the waveforms shown, determine the sequence of digits that appear on the dispaly When a HIGH is on the output of the decoding circuit below, what is die binary code appearing on die inputs?

Explanation / Answer

1)

B3 B2 B1 B0 Y0 Y1 Y2 Y3 Y4 Y5 Y6 Y7 Y8 Y9

0    0   0   0   0 1 1 1 1 1 1 1 1 1

0    0 0 1 1 0 1 1 1 1 1 1 1 1

0   0   1    0   1 1 0 1 1 1 1 1 1 1

0   0   1    1    1 1 1 0 1 1 1 1 1 1

0   1   0    0    1 1 1 1 0 1 1 1 1 1

0   1   0    1    1 1 1 1 1 0 1 1 1 1

0   1    1 0     1 1 1 1 1 1 0 1 1 1

0   1    1 1     1 1 1 1 1 1 1 0 1 1

1   0    0   0      1 1 1 1 1 1 1 10 1

1   0    0    1     1 1 1 1 1 1 1 1 1 0

2)55-21= 0101 0101-0010 0001

2'S COMPLEMENT OF 21=1101 1111

=0101 0101+1101 1111

=100110100

3)priority encoder priority is assigned to each input even more than one input is asserted the input which is having highest priority is represented on the output

4)a) 10011001=01100110+1=01100111= - 103

b) 01110100=116

c)10111111=01000000+1=01000001= -65

5) for the given selection line the out put of mux is y=1

6) the truth table of given circuit is

A0 B0 SUM Cout

0 0

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