(EOC Q20) What is the ATP yield when dihydroxyacetone phosphate is completely ox
ID: 181019 • Letter: #
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(EOC Q20) What is the ATP yield when dihydroxyacetone phosphate is completely oxidized to CO2 by a mammalian liver cell homogenate? Assume that glycolysis, the citric acid cycle, and oxidative phosphorylation are fully active. (Hint: what NADH transport system will be preferred in the liver?)
(EOC Q20) What is the ATP yield when dihydroxyacetone phosphate is completely oxidized to CO2 by a mammalian liver cell homogenate? Assume that glycolysis, the citric acid cycle, and oxidative phosphorylation are fully active. (Hint: what NADH transport system will be preferred in the liver?)
17 16 14.5 13.5 12Explanation / Answer
Dihydroxy Acetone Phosphate underges 5 steps to form Pyruvate marking the end of glycolysis.
As a result 1 NADH and 2 ATPs are formed.
Pyruvate undergoes oxidative decarboxyllation and forms Acetyl Co A resulting in the formation of 1 NADH.
Acetyl Co A is completely converted to Carbon dioxide througj Kreb's Cycle which yeilds 3 NADH, 1 FADH2 and 1GTP(ATP euivalent).
By now we have a total of 5 NADH, 1 FADH2 and 3 ATPs.
Each NADH produces 2.5 ATP through oxidative phosphorylation. Similarly, each FADH2 will produce 1.5 ATP.
5NADH X 2.5 ATP = 12.5 ATPs
1FADH2 X 1.5 ATP = 1.5 ATP
2 ATP
1 GTP(ATP)
So, on completely oxidising 1 molecule of Dihydroxy Acetonephosphate to Carbon dioxide will yield 17 ATPs.
First option is correct.
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