Given the following expression: V = 240 cos(240 pi t + 60 degree ) v, find: Vrms

Question

Given the following expression: V = 240 cos(240 pi t + 60 degree ) v, find: Vrms v Frequency, f Hz Omega ( Omega ) rad/s Period, T bs. V at t = 5 ms v The expression for v as a phasor: v T F The angle (60 degree ) serves to move the plot of v to the right on the time axis. Given the ideal transformer shown below with primary/secondary turns ratio of 1 : 2 , what is the effective value of the load resistor reflected back to the primary side? Z in = Z L/ a2 Zin = Ohm . T F For the same transformer, v2 = v1/2. T F For the same transformer l2 = l1/2.

Explanation / Answer

1. Vrms = 240/2 = 169.7 V;

2. f = /2 = 240/2 = 120/ = 38.19Hz;

3. = 240 rad/sec;

4.period = 1/f = 1/38.19 = 0.02618 sec;

5. V at 5 ms = 239.15 V ;

6 .v = 240(240t+/3);

7. TRUE;

8. Z = 10/22 = 2.5;

9. FALSE ;

10. TRUE

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