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need help with part F through K, including number 2. Thanks! Att=0, a block of m

ID: 1796296 • Letter: N

Question

need help with part F through K, including number 2.

Thanks!

Att=0, a block of mass m =360 kg at rest on the end of a horizontal spring is pushed to the left compressing the spring a distance of 24.0 cm by a force of 105.6 N. The block is then released and the system undergoes SHM (simple harmonic motion). a) Determine the spring constant k I 57/ b) Determine the period and frequency of the motion. c) Determine the amplitude d) Determine the maximum velocity and the displacement x at which this occurs. 64 e l arr ido e) Determine the maximum acceleration and the displacement(s) x at which this occurs f Determine the total energy of the system. PE KE g) Determine the kinetic energy when x 0. 714 h) Determine the velocity of the block when x = 0. i) Determine the potential energy when x 14 cm. j) Determine the kinetic energy when x 14 cm. k) Determine the velocity of the block when x = 14 cm. 2. A simple pendulum has a length of 0.450 m. What is its period and frequency?

Explanation / Answer


1)


m=3.6 kg


force, F=105.6 N


compression, x=24cm


a)


F=k*x_max


105.6=k*0.24


===> k=440 N/m

b)


time period, T=2pi*sqrt(m/k)


T=2pi*sqrt(3.6/440)


T=0.57 sec


frequency, f=1/T


f=1/(0.57)


f=1.76 Hz

c)

ampitude, A=24cm

d)

Vmax=A*w


=0.24*(2pi/T)


=0.24*(2pi/0.57)


=2.64 m/sec


at x=0 ==> velocity is maximum

e)

amax=w^2*A


=(2pi/T)^2*A


=(2pi/0.57)^2*(0.24)


=29.2 m/sec^2


at x=A(maximum displacement) ==> acceleration is maximum

f)


T.E=1/2*K*A^2


=1/2*440*0.24^2


=12.67 J


g)


at x=0, T.E=K.E=1/2*m*v_max^2


K.E=12.67 J

h)

at x=0, velocity is maximam,


vmax=2.64 m/sec

i)

at x=14cm


P.E= 1/2*m*w^2*x^2


=1/2*3.6*(2pi/0.57)^2*0.14^2


=4.29 J

j)

here,


T.E=K.E+P.E


12.67=K.E+4.29


==> K.E=8.38 J


k)


at x=14cm


velocity v=w*sqrt(A^2-x^2)


v=(2pi/0.57)*sqrt(0.24^2-0.14^2)


v=2.15 m/sec

2)


period T=2pi*sqrt(l/g)

T=2pi*sqrt(0.45/9.8)


T=1.34 sec


and

frequency f=1/T


f=1/(1.34)


f=0.743 Hz