(13%) Problem 4: Consider the compound optical system shown in the diagram, wher
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(13%) Problem 4: Consider the compound optical system shown in the diagram, where two thin lenses of focal lengths 7.5 cm (left lens) and 38 cm (right lens) are separated by a distance 26 cm. ©theexpertta.com 13% Part (a) If an object is placed a distance do >f to the left of the first lens (the left lens), will the resulting image from the first lens be real or virtual, and inverted or upright? Grade Summary Deductions Potential Virtual, InvertedOReal, UprightOReal, Inverted OVirtual, Upright 0% 100% Submit Hint Submissions Attempts remaining: 3 (33% per attempt) detailed view Hints: 1 % deduction per hint. Hi ints remaining: 1 Feedback: 0%-deduction per feedback. 13% Part (b) If a 2.9 cm tall object is placed as indicated in part (a), and the image formed is 0.71 cm tall, what is the magnification of the first lens? 13% Part (c) Using the information from part (b), calculate the image distance, in centimeters, from the first lens D 13% Part (d) Does the image formed by the first lens serve as a real or a virtual object for the second lens? 13% Part (e) What is the image distance, in centimeters, for the second lens? D 13% Part (f) What is the magnification of the second lens? 13% Part (g) what is the total magnification of this compound optical system? 13% Part (h) Is the image created by the second lens real or virtual? Is it upright or inverted?Explanation / Answer
(A) d0 > f1 then image will be real and inverted.
(b) m = - 0.71 / 2.9 = - 0.245
(C) m = - di / d0 = - 0.245 = - di / do
di = 0.245 d0
Applying 1/f = 1/do + 1/di
1/7.5 = 1/do + 1/0.245do
do = 38.1 cm
di = 0.245 d0 = 9.34 cm
(d) real object
(e) for second lens, do' = 26 - 9.34 = 16.7 cm
f' = 38 cm
1/f' = 1/do' + 1/di'
di' = - 29.7
(f) m = - di'/do' = 1.8
(g) m = 1.8 x -0.245 = - 0.435
(h)virtual. final image is inverted as compare to object.
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