4. In a “Projectiles\" experiment the two curves were fitted to the equations (P

Question

4. In a “Projectiles" experiment the two curves were fitted to the equations (Please note: this question is entirely separate from question 1. These data were obtained for a projectile launched at a different angle with a different initial velocity. It would make no sense to use any results from that question here) x=mt + b ; m=4.9 m/s; b=-0.026 m Fill out the table below y=At" + Bt+C; A=-5.2 ; B=3.5; C=-0.049 Initial v Initial vy Magnitude of initial v Launch angle % error in the value of g (theoretical value g=-9.8 m/s") Time to the top Maximum height Vx at the top Vy at the top Range of the projectile Sketch the x- and y- position graphs for this motion. Make sure that the graph shows a) whether v or vy is larger b) the time the max height was reached, and what that max height was c) the time the range (max x) was reached, and what that range was 1.6 1.4 1.2 1 0.8 0.6 0.4 0.2 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8

Explanation / Answer

INITIAL Vx= dx/dt = m = 49 m/s

Initial Vy = dy/dt = 2AT + B = 2*(-5.2)(0)+3.5 = 3.5 m/s

Magnitude of intial velocity = square root of (Vx2 + Vy2) = 49.124

time to top t = 2uy/g = 2*3.5/9.8 = 0.714 sec

maximun height = 0.628 m

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