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Question
dit View History bprod.stjohns.edu/bbcswebdav/pid-1419407-dt-content-ri Hel d-91 98294_1 / courses/SC1-1000C-0-75236-201 770/HomeworkA20Assignment%204 nMe bbeswebdav/pid-1419407-dt-content-rid-91982941/courses/SCI-1000C-0-75236-201770/Homewor isney ESPN 2 t - MysJu ns.edu/bbcswebdav/ Each problem is worth 10 points. The bonus problem you can get is 110 0 points each. The total points An airplane accelerates down a runway at 3.20 m/s for 32.8 s until it finally lifts off the ground. Determine the distance before takeoff 1. 2. A feather is dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 ml s2. Determine the time for the feather to fall to the surface of the moon. 3. A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 m. Determine the acceleration of the bike. 4. A car traveling at 22.4 m/s skids to a stop in 2.55 s. Determine the skidding distance of the car (assume uniform acceleration). 5. A skateboarder, starting from rest, rolls down a 12.0 m ramp. When she arrives at the bottom of the ramp her speed is 7.70 m/s. a) Determine the magnitude of her acceleration, assumed to be constant b) If the ramp is inc lined at 25 degrees with respect to the ground, what is the component of her acceleration that is parallel to the ground?Explanation / Answer
Solution:
1) Using S = 0.5 * a * t^2
=> S = 0.5 * 3.20 * 32.8^2
=> S = 1721.344 meter ( distance)
2) Using , t = sqrt( 2h / g)
=> t = sqrt ( 2 *1.40 / 1.67 )
=> t = 1.29 second.
3) Using , V^2 - U^2 = 2 * a * S
=> 7.10^2 - 0 = 2 * a * 35.4
=> a = 0.712 m/s^2
4) using v = u + a*t
=> 0 = 22.4 + a * 2.55
=> a = -8.78 m/s^2
Now using v^2 - u^2 = 2 * a * s
=> 0 - 22.4^2 = 2 * ( -8.78 ) * s
=> s = 22.57 meter
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