A laboratory electromagnet produces a magnetic Seld of magnitude 1.49 T. A proto

Question

A laboratory electromagnet produces a magnetic Seld of magnitude 1.49 T. A proton moves through this field with a speed of 6.58 x 10 m/s (a) Find the magnitude of the maximom magnetic force that could be exerted on the proton (b) What is the magnitude of the maximum acceleration of the proton? m/s (c) Would the field exert the same magnetic force on an electron moving through the field with the same speed? (Assume that the electron is moving in the same direction as the proton.) O Yes This answer has not been gaded yet

Explanation / Answer

We know that,

Charge on proton = +1.60 * 10^-19 Coulombs

Mass of proton = 1.67265 * 10^-27 kg

Charge on electron = -1.60 * 10^-19 Coulombs

Mass of electron = 9.11 * 10^-31 kg

a]  Magnetic force = charge * velocity * magnetic field

= +1.60 * 10^-19 * 6.58 * 10^6 * 1.49 T

= 1.57 * 10^-12 N

b] Force = mass * acceleration

a = Force/ mass

= 1.57*10^-12/(1.67265*10^-27)

= 9.386 * 10^14 m/s^2

c]  Because the charge of the electron is negative, the force that the magnetic field exerts on the electron will be in the opposite direction.

Magnetic force = -1.57 * 10^-12 N

d]  Force = mass * acceleration

a = F/m

= -1.57*10^-12/(9.11*10^-31)

= -1.723 * 10^18 m/s^2

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