A conducting bar of length f moves to the right on two frictionless rails as sho

Question

A conducting bar of length f moves to the right on two frictionless rails as shown in the figure below A uniform magnetic field directed into the page has a magnitude of 330 T. Assume R-9.10 and 0.320 m Bin xXXxXXx (a) At what constant speed should the bar move to produce an 8.40-mA current in the resistor? m/s (b) What is the direction of the induced current? clockwise O counterclockwise into the page O out of the page (c) At what rate is energy delivered to the resistor? (d) Explain the origin of the energy being delivered to the resistor.

Explanation / Answer

a)

I=V/R where V=BLv

Therefore I=BLv/R

Then v=IR/BL

I=8.4mA=0.0084A

R=9.10 ohms

B=0.330T

L=0.320m

so v=(0.0084*9.10)/(0.330*0.32)= 0.724m/s

c)

rate at which energy delivered is

E=I^2R=(0.0084^2)*9.10 = 6.42*10^-4W = 0.642mW

d) Origin of energy being delivered to resistor is from magnetic field.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.