A neon sign that requires a voltage of 10000 V is plugged into a 120 V wall outl

Question

A neon sign that requires a voltage of 10000 V is plugged into a 120 V wall outlet. What ratio of turns (primary/secondary) must the transformer have to power the sign?

(NP / NS) = _____________

Even for an ideal transformer, we can't get "something for nothing". Since this transformer steps up the voltage, what must be decreased? (Power, Current, Resistance)

The output of this transformer will have (less, more, same) charge carriers, each carrying (Less, More, Same) energy, as compared to the input.

Explanation / Answer

1) We want to step up from 120 V to 10,000 V, a factor of 83.33. That means that the secondary coil must have 83.33 times the number of loops in the primary coil.

NP/NS = 1/83.33

2) Current

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