Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

h Chapter 17 B × How Much En × Department o x Physics 111 L x Course Home × Mast

ID: 1790181 • Letter: H

Question

h Chapter 17 B × How Much En × Department o x Physics 111 L x Course Home × MasteringPhy: × E MasteringPhyx The Batteries Anthony C Secure https://session.masteringphysics.com/myct/itemView?assignmentProblemID-80352448 Apps h MoodleRutgers BPipelineSoundcloud Acid/Base Calculations Weak Acid Equilibrium Department of Physics Group Activity: SI C.. HWO Exercise 26.24 Resources « previous 1 of 14 next Exercise 26.24 Part A Find the current through the 30.0 resistor The batteries shown in the circuit in the figure (Figure 1) have negligibly small internal resistances. 0.433 Submit My Answers Give Up Incorrect; Try Again; 5 attempts remaining Part B Figure 1of Find the current through the 20.0 resistor != 10.22 +30.0 20,042 0.0 V Submit MyAnswer GiveUp 5.00 V Incorrect; Try Again; 6 attempts remaining Part C Find the current through the 10.0 V battery

Explanation / Answer

let current in left loop is i1 and right loop is i2.

both are assumed to be in clockwise direction.

writing KVL for left loop:

10-30*(i1-i2)=0

==>30*(i1-i2)=10…(1)

writing KVL for right loop:

-30*(i2-i1)-20*i2-5=0

==>30*i1-50*i2=5….(2)

solving equation 1 and 2 simultaneously,

i2=0.25 A

i1=0.583 A

part A:

current through 30 ohms resistor =i1-i2=0.333 A

part B:

current through 20 ohms resistor=i2=0.25 A