A bicycle tire is spinning counterclockwise at 2.30 rad/s. During a time period

Question

A bicycle tire is spinning counterclockwise at 2.30 rad/s. During a time period t = 2.45 s, the tire is stopped and spun in the opposite (clockwise) direction, also at2.30 rad/s. Calculate the change in the tire's angular velocity and the tire's average angular acceleration av. (Indicate the direction with the signs of your answers, choosing the counterclockwise direction as positive.)

a) find the change in the tire's angular velocity (rad/s)

b) find the tire's average angular acceleration (rad/s2)

Explanation / Answer

change in angular velocity = wf - wi

= - 2.30 - 2.30

= - 6.40 rad/s .........Ans

average acceleration = delta(w) / t

= - 6.40 / 2.45

= - 2.61 rad/s^2 ..........Ans

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