Sapling Learning macmillan learning Calculate the magnitude of the linear moment

Question

Sapling Learning macmillan learning Calculate the magnitude of the linear momentum of a 63.9-kg object on the Equator, as measured from the center of Earth. The radius of the Earth is 6371 km. Number Po=129.5 x 103 | kg·m/s Define the time at which you calculated your previous result asto. What is the magnitude of the net change Ap in the object's momentum in the six hours following t? Number kg m/s Now calculate the magnitude of the total change in the object's momentum 12 hours after Number kg m/s

Explanation / Answer

w = 2 pi / T = 2 pi / (24 x 3600) = 7.272 x 10^-5 rad/s

v = w r = (7.272 x 10^-5) (6371 x 10^3)

v = 463.3 m/s

p0 = m v = 2.96 x 10^4 kg m/s .........Ans

delta(p1) = p0 i + p0 j

magnitude = sqrt(2.96^2 + 2.96^2) x 10^-4

= 4.19 x 10^4 kg m/s ........Ans

delta(p2) = 2p0 = 5.92 x 10^4 kg m/s ...Ans

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