(a) What is the magnitude of the tangential acceleration of a bug on the rim of

Question

(a) What is the magnitude of the tangential acceleration of a bug on the rim of an 11.0-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 79.0 rev/min in 4.50 s? m/s2 (b) When the disk is at its final speed, what is the magnitude of the tangential velocity of the bug? m/s (c) One second after the bug starts from rest, what is the magnitude of its tangential acceleration? m/s2 (d) One second after the bug starts from rest, what is the magnitude of its centripetal acceleration? m/s2 (e) One second after the bug starts from rest, what is its total acceleration? (Take the positive direction to be in the direction of motion.) magnitude m/s2 direction ° from the radially inward direction

Explanation / Answer

a)79 rpm = 79*6.28*0.11*2.54= 138.62 m/sec

Tangential acceleration = 138.62/4.5= 30.8 m/sec^2 ( ans)

b) speed , tangential velocity = 138.62 m/sec ( ans)

c) tangential acceleration= 30.8 m/sec^2 (ans)

d) speed after 1 sec = 30.8 m/sec

So centrepetal acceleration = 30.8^2/0.11*2.54 = 3395.27 m/sec^2 ( ans)

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.