(a) What is the magnitude of the tangential acceleration of a bug on the rim of
ID: 1783498 • Letter: #
Question
(a) What is the magnitude of the tangential acceleration of a bug on the rim of a 13.0-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 75.0 rev/min in 3.90 s?
m/s2
(b) When the disk is at its final speed, what is the magnitude of the tangential velocity of the bug?
m/s
(c) One second after the bug starts from rest, what is the magnitude of its tangential acceleration?
m/s2
(d) One second after the bug starts from rest, what is the magnitude of its centripetal acceleration?
m/s2
(e) One second after the bug starts from rest, what is its total acceleration? (Take the positive direction to be in the direction of motion.)
Explanation / Answer
given n = 77 rpm = 75/60 = 1.25 rev/sec
Thus by = 2n = 2 x 3.14 x 1.25 = 7.85 rad/sec
Thus by (final) = (initial) + t
=>7.85 = 0 + 3.9
=> = 3.95 rad/sec^2
Thus by a = r = (13/2) x 2.54 x 10^-2 x3.95 {as 1in = 2.54 cm & 1 cm = 10^-2m}
=>a = 0.66 m/s^2
By v = r = (13/2) x 2.54 x 10^-2 x 7.85 = 1.30 m/s
By a = r =0.66 m/s^2
angular acceleration() = 3.95 rad/sec^2
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