Section 5.7 7. 0/4 points I CJ10 5 P046 Interactive Solution 5.47 offers help in

Question

Section 5.7 7. 0/4 points I CJ10 5 P046 Interactive Solution 5.47 offers help in modeling this problem. A stone is tied to a string (length - 0.500 m) and whirled in a circle at the same constant speed in two different ways. First, the circle is horizontal and the string parallel to the ground. Next, the circle is vertical. In the vertical case the maximum tension in the string is 16 horizontal. Determine the speed of the stone. 30.62 I 0% larger than the tension that exists when the cre is X m/s Additional Materials Section 5.7 Ask Your m.secondsaetitem, has a circular orbit around this same planet. The orbit of this second satellite has a radius of 8.45 x 105 m. What is the orbital speed of the second satelite? 12041.7 A satellite is in a circular orbit around an unknown planet. The satellite has a speed of 1.55 x lgdmys, and the radius orthe orbit s S10x m/s

Explanation / Answer

Tmin = 0.16 T

Tmin will be at top of circle,

Tmin + m g = m v^2 / R

Tmin = m ( v^2/R - g)

and T = m v^2 / R

m v^2 / R - m g = 0.16 m v^2 / R

0.84 m v^2 / R = m g

  
v = sqrt(0.50 x 9.81 / 0.84) = 2.42 m/s .......Ans

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