Help > 51% i) Wed 509 PM HW 8 - ao -14 points CJ10 5.P046 e Solution 5.47 offers

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Help > 51% i) Wed 509 PM HW 8 - ao -14 points CJ10 5.P046 e Solution 5.47 offers help in modeling this problem. -Ask Your Teac Notes A stone is tied to a string (length 0.500 m) and whirled in a circle at the same constant speed in two different ways. First, the circle is horizontal and the string is neartly parallel to the ground. Next, the circle is vertical. In the vertical case the maximum tension in the string is 16.0% larger than the tension that exists when the crete is horizontal. Determine the speed of the stone. m/s Additional Materials Section 5.7 Answers CJ10 5 P033. 8. O 4/4 points I the orbit is 5.10 x 10% m. A second satelie also has a circular orbit around this same planet. The orbit of this second satellite has a radius of 8.45 x 106 m. What 12041.7 A satellite is in a circular orbit around an unknown planet. The satellite has a speed of 1.55 x 104 is the orbital speed of the second satellte? m/s Section 5.6

Explanation / Answer

Solving 1st question

Let the speed be v m/s

For horizontal

T=mv*v/r...........(1)

For vertical

T'=m*v*v/R + mg.......(2)

Given T'=T+0.16T=1.16T

Dividing (2) by (1)

1.16=1+(g*R/v)

We got v=30.625 m/s

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