LTE.. 99% 23:50 shopper in a supermarket pushes a cart with a rce of 42 N direct

Question

LTE.. 99% 23:50 shopper in a supermarket pushes a cart with a rce of 42 N directed at an angle of 25" below e horizontal. The force is just sufficient to ercome various frictional forces, so the cart oves at constant speed (a) Find the work done by the shopper as she moves down a 47.0-m length aisle (b) What is the net work done on the cart? 40FF Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully Why? Thie answer has not been graded yet. (c) The shopper goes down the next aisle, pushing horizontally and maintaining the same speed as before. If the work done by frictional forces doesn't change, would the shopper's applied force be larger, smaller, or the same? What about the work done on the cart by the shopper?

Explanation / Answer

Problem 1)

a) Answered

b) Since the cart is moving with constant velocity,Fnet = ma = m(0) = 0

Net force is zero, so net work done on the cart is also 0 J

c) The shopper's force along the horizontal component would be larger since all of the forces now directed horizontally, even though the shopper is pushing with the same force as before. The work done would be larger also, because now =0 and W=Fdcos is larger than it was before.

W = 42 x 47 x cos 0° = 1974 J

According to Chegg guidelines I can answer one question at a time, so please post other questions separately. Please rate my answer if you find it helpful, good luck...

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