The anterior cruciate ligament in a woman\'s knee is 2.5 cm long and has a cross

Question

The anterior cruciate ligament in a woman's knee is 2.5 cm long and has a cross-sectional area of 0.54 cm2. If a force of 3490 N is applied longitudinally, how much will the ligament stretch? The Young's modulus is YACL 0.1 x 109 N/m2. .01615 A woman's ACL experiences a tension of 3490 N. We can calculate the distance the ligament stretches from the original length of the ligament, the cross- sectional area of the ligament, and the Young's modulus. The ACL is 2.5 cm long and has a cross-sectional area of 0.54 cm2. The Young's modulus of the ACL is 0.1 x 109 N/m2. cm Supporting Materials Pcast eBook

Explanation / Answer

Here ,

let the change in length is x

strain = stress/young modulus

x/2.5 = (3490/(0.54 *10^-4))/(0.1 *10^9)

solving for x

x= 1.61 cm

the ligament will stretch by 1.61 cm

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