b. Now let\'s work the problem(s). Start with the astronaut\'s jump on Earth. Dr
ID: 1787298 • Letter: B
Question
b. Now let's work the problem(s). Start with the astronaut's jump on Earth. Draw a sketch. bh Before you collect your knowns and unknowns, you need to identify your coordinate system, both the location of the origin and the direction that is positive. On your sketch for part b, draw an arrow showing which way will be the positive direction, and label it +y. Also label where y = 0. c. d. Now you can make sure that the signs of your velocities and acceleration are internally consistent. Dravw another arrow, labelling it a, showing the direction of the acceleration due to gravity. Is your acceleration going to be positive or negative? Why? You also need to decide your starting point and ending point. In this problem, it makes sense to have yo on the ground just as the jump is starting. You know that the astronaut is going to go up and then come back down, so you have a choice of "ending" points -when the astronaut is at his highest point, or when the astronaut comes back to the ground e. For this problem, it makes the most sense to have your "1" variables when the astronaut is at his highest point. Why? beCarr, @ hight paint V. point why? f. Ok, so now you can fill in your variables. Vo= e. One thing has changed about the table of variables. What is it? Why did we do this? Before thinking about equations, make sure you have thought through everything you know. You should have values for all the variables except vo and t, h.Explanation / Answer
as the parts b, c, d , e have already been answered
f. yo = 0
y1 = h ( height to which the astronaut jumps)
vo = ?
v1 = 0
t0 = 0
t1 = t
ao1 = -g = -9.81 m/s/s
g. the acceleration is -ve as the acceleration due to gravity points downwards
i. solving for initial vellocity will tell us how much the astronaut accelerated in the distance dy
j. to solve for vo
2*ao1*y1 = v1^2 - vo^2
vo = sqrt(2*g*h)
we used this equation as h is known and sho is v1
k. hence
vo = sqrt(2*g*h)
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