3(1 pt) Suppose the particle in a Rutherford scattering experiment is replaced w

Question

3(1 pt) Suppose the particle in a Rutherford scattering experiment is replaced with a proton of the same initial kinetic energy and also headed directly toward the nucleus of the gold atom. Will the distance from the center of the nucleus at which the proton stops be (a) greater than, (b) less than, or (c) the same as that of the particle? 4. (1 pt) Problem continued: If, instead we switch the target to a nucleus with a larger Z, is the stopping distance of the particle (a) greater than, (b) less than, or (c) the same as originally?

Explanation / Answer

lesser than alpha particle, because of two reasons, a proton with same kinetic energy as alpha particle will have a much higher initial velocity, and charge on a proton is half of charge on alpha particle resulting in proton experiencing the lesser force of repulsion as compare to the alpha particle.

b)Z indicates the number of protons in nucleus or charge,

With a higher charge, the force of repulsion will be greater on alpha a particle, resulting in much higher force of repulsion, hence greater stopping distance

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