a) The index of refraction for flint glass can be calculated using n(A)= 1.670+7
ID: 1786248 • Letter: A
Question
a) The index of refraction for flint glass can be calculated using n(A)= 1.670+7430 nma2, where is measured in nanometers. If a ray of red light ared=650 nm) in air is incident on a glass pane as shown, what will be its transmission angle for a ray inside the prism, ? (Keep at least three sig figs.)l 550 b) Find x, the horizontal displacement of the ray as it traverses the glass of thickness (Keep at least three sig figs.) 0.200 m. c) If the red ray from #aand #b is replaced by a violet ray (Aviolet=425 nm), what is x? Also determine the lateral spread of the beam, x=kred_Xviole!Explanation / Answer
(A) n = 1.670 + (7430/650^2) = 1.687
Applying Snell's law,
ni sin(i) = nr sin(r)
sin55 = 1.687 sin(theta1)
theta1 = 29 deg
(B) tan29 = x / L
x = 0.200 tan29 =0.111 m
(c) n = 1.670 + 7430/425^2 = 1.711
sin55 = 1.711 sin(theta1)
theta1 = 28.6 deg
x = 0.200 tan28.6 = 0.109 m .......Ans
delta(x) = 0.111 - 0.109 = 0.002 m Or 2 mm
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