Torque 1) If you have two masses balanced on a meter stick like the setup we had

Question

Torque 1) If you have two masses balanced on a meter stick like the setup we had for this lab with a mass on either side of the fulcrum, and you added 50g to the first mass, how would you need to move the second mass to rebalance the meter stick?

2)If you have one mass on each side of the meter stick like in the previous question, and you add a mass to the first side, how would you need to move the mass on the second side to rebalance the meter stick?

3) Between which two points do you measure the distances for torque?

4) What was the relationship you saw between the hanging masses, their distances from the fulcrum, and the torque they exerted on the system?

5) Please include a real world example of torque, making sure to explain why your example demonstrates torque.

Explanation / Answer

The torque has to be balance.

Torque = distance x force

1. Since the force has increased on one side, to balance it the other mass has to be moved away from the pivot to balance the torque.

2. The mass on the second side has to be moved away from the pivot.

3. The distance is measured from the fixed point(pivot/fulcrum) and the point where the force in acting.

4. Torque = distance (cross product) Force(=mg)

5. While opening a door, one has to exert a torque which acts on the hinge.

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