26)14 pts] V-40 V and the battery is ideal , what is the current through R3 in t

Question

26)14 pts] V-40 V and the battery is ideal , what is the current through R3 in the figuret 20 Rs-20 R4-30 27) 14 pts) A proton moving at 2.0 104 m/s horizontally directed vertically downward. What magnitude force acts on the proton due enters a region where a magnetic field of 0.24 T is present, to this field? (e-1.60× 10-19C) 25) 15 pts] In the figure, a small particle of charge -19 10-6 C and mass m-3.1 10-12 has speed wo- 4000 m/s as it enters a region of uniform magnetic field. The particle is initially traveling perpendicular to the magnetic field and is observed te travel in the semicircular path shown with radius R-5.0 cm. Find the magnitude and direction of the magnetic field in the region. Region of magnetic field I Path of the i particle /n

Explanation / Answer

26) R2 and R3 are in parallel,

R = R2 R3 / (R2 + R3) = 10 ohm

now R1, R and R4 are in series,

Req = R1 + R + R4 = 50 ohm

current through battery, I = V / Req = 0.8 A

I3 = 0.8 /2 = 0.4 A .......Ans

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