A Girl on a Trampoline Part A A girl of mass mi = 60.0 kilograms springs from a

Question

A Girl on a Trampoline Part A A girl of mass mi = 60.0 kilograms springs from a trampoline with an initial upward velocity of8.00 meters per second. At height h 2.00 meters above the trampoline, the girl grabs a box of mass m215.0 kilogramS. (Figure 1) What is the speed Tbefore of the girl immediately before she grabs the box? Express your answer numerically in meters per second. Hints For this problem, use g-9.80 meters per second per second for the magnitude of the acceleration due to gravity Ubefure:- m/s Figure 011 Submit My Answers Give Up Part B What is the speed vafter of the girl immediately after she grabs the box? Express your answer numerically in meters per second. Hints Vafter n s Submit My Answers Give Up

Explanation / Answer

1]  By v^2 = vi^2 -2gs

vbefore^2 = (8)^2 - 2 * 9.8 * 2

vbefore = sqrt(8^2 - 2*9.8*2)

= 4.98 m/s

2] By the law of momentum conservation

m1u1+m2u2 = (m1+m2) * v after

60 * 4.98 + 0 = (60+15) * v after

vafter = 60*4.98/(60+15) = 3.98 m/s Answer

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