A flywheel with a radius of 0.400 m starts from rest and accelerates with a cons

ID: 1784616 • Letter: A

Question

A flywheel with a radius of 0.400 m starts from rest and accelerates with a constant angular acceleration of 0.900 rad/s2 .

I need help with part C,F, and I

Part A. Compute the magnitude of the tangential acceleration of a point on its rim at the start. Answer: atan = 0.360 m/s2

Part B. Compute the magnitude of the radial acceleration of a point on its rim at the start. Answer: arad = 0 m/s2

Part C. Compute the magnitude of the resultant acceleration of a point on its rim at the start.

Part D. Compute the magnitude of the tangential acceleration of a point on its rim after it has turned through 60.0 . Answer: atan = 0.360 m/s2

Part E. Compute the magnitude of the radial acceleration of a point on its rim after it has turned through 60.0 . Answer: arad = 0.745 m/s2

Part F. Compute the magnitude of the resultant acceleration of a point on its rim after it has turned through 60.0 .

Part G. Compute the magnitude of the tangential acceleration of a point on its rim after it has turned through 120.0 . Answer: atan = 0.360 m/s2

Part H. Compute the magnitude of the radial acceleration of a point on its rim after it has turned through 120.0 . Answer: arad = 1.51 m/s2

Part I. Compute the magnitude of the resultant acceleration of a point on its rim after it has turned through 120.0 .

Part C ) resultant acceleration ( a) = (atan^2 + arad^2)

So,

a = (0.36^2 + 0^2) = 0.36 m/s^2

a = 0.36 m/s^2

Part F) At = 60°, resultant acceleration (a) is

a = (atan^2 + arad^2)

a = (0.36^2 + 0.745^2 )

a = 0.827 m/s^2

Part I ) = 120°

a = (atan^2 + arad^2)

a = (0.36^2 + 1.51^2)

a = 1.55 m/s^2

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