(10%) Problem 6: A 1925 kg child is riding a playground merry-go-round that is r
ID: 1783951 • Letter: #
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(10%) Problem 6: A 1925 kg child is riding a playground merry-go-round that is rotating at 444 rev/min 25% Part (a) What net force is acting on her if she is standing on the merry-go-round 1.1 m from its center in newtons? The net force in this situation is sometimes called "centripetal force" 25% Part(b) What net force (in N) Is acting on her if she is standing on an amusement park merry-go-round that rotates at 3.6 rpm and she is 7.3 m from its center? Grade Summary Deductions Potential Fe2 = 3.011 2% 98% 7 89 HOME cos0 asin) atanO acotan)sinhO cosh)tanh) cotanhO °Degrees Radians sin) cotanas tanOt ( acosO Submissions Attempts remaining: 5 (1% per attempt) detailed view 23 - 1% 1% 0 END O BACKSPACE D CLEAR Submit Hint T give up! Hints: 1 % deduction per hint. Hi nts remaining: 2 Feedback: 1% deduction per feedback là 25% Part (c) How many times her weight is the force in part (a)? 25% Part (d) How many times her weight is the force in part (b)? All content 2017 Expert TA, LLCExplanation / Answer
a)net force = m r w2
= 19.25 * 1.1 * [44.4 * 2 pi /60]2
= 457.77 N
b)net force = m r w2
= 19.25 * 7.3 * [3.6 * 2 pi /60]2
= 19.97 N
c) w = 19.25 * 9.8 * Fnet / 457.77
= 0.412 Fnet
d) w' = 19.25 * 9.8 * Fnet / 19.97
= 9.44 Fnet
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