(10%) Problem 6: A Christmas light is made to flash via the discharge of a capac

Question

(10%) Problem 6: A Christmas light is made to flash via the discharge of a capacitor. The effective duration of the flash is 0.25 s of 3.15 V which you can assume is the time constant of the capacitor), during which it produces an average 35 mW from an average voltage - 25% Part (a) How much energy, in Joules, does it dissipate? 25% Part (b) How much charge, coulombs, moves through the light? 25% Part (c) Find the capacitance of the light, in farads. 25% Part (d) What is the resistance, in ohms, of the light? -

Explanation / Answer

Energy = power X time

Energy = 35 X 10-3  X 0.25

Energy = 8.75 X 10-3 J

b) Energy in a capacitor = (1/2)QV

8.75 X 10-3 = 0.5Q(3.15)

Q = 5.55 X 10-3 C

c) Q = CV

C = Q/V

C = 5.55 X 10-3 / 3.15

C = 1.76 X 10-3 F

d) I = Q/t

I = 5.55 X 10-3 / 0.25

I = 2.22 X 10-2 A

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