1. A 12-kg wooden crate rests on the floor (which is horizontal), with the coeff

Question

1. A 12-kg wooden crate rests on the floor (which is horizontal), with the coefficient of static friction between the crate and the floor being 0.60. You then push on the crate with a force of magnitude 55 N that is directed parallel to the floor. Note: Be very careful with your analysis; remember that the magnitude of static friction in general varies between zero and a maximum value of ,N (a) What is the magnitude of the static friction force that acts on the crate? (b) What is the net force acting on the crate? From your answer to this question, determine whether the crate will move or not

Explanation / Answer

maximum friction force = umg = 0.6 x 12 x 9.81 = 70.632 =fmax

Fapplied = 55N < fmax

so, friction force that acts will be 55N

a.)55N

b.) Net force = F-friction = 55-55 = 0N

the net force is zero, so the block doesn't move

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