1. A 12-kg wooden crate rests on the floor (which is horizontal), with the coeff

Q: 1. A 12-kg wooden crate rests on the floor (which is horizontal), with the coeff

here, mass , m = 12 kg us = 0.6 a) ffs = us * m * g ffs = 0.6 * 12 * 9.81 N ffs = 70.6 N as ff > applied force the static friction force is equal to applied force the magnitude of static frictional force is 55 N b) the crate will not move the net force on the crate is zero

ID: 1779254 • Letter: 1

Question

1. A 12-kg wooden crate rests on the floor (which is horizontal), with the coefficient of static friction between the crate and the floor being 0.60. You then push on the crate with a force of magnitude 55 N that is directed parallel to the loor. Note: Be very careful with your analysis; remember that the magnitude of static friction in general varies between zero and a maximum value of ,N (a) What is the magnitude of the static friction force that acts on the crate? b) What is the net force acting on the crate? From your answer to this question, determine whether the crate will move or not

Explanation / Answer

here,

mass , m = 12 kg

us = 0.6

ffs = us * m * g

ffs = 0.6 * 12 * 9.81 N

ffs = 70.6 N

as ff > applied force

the static friction force is equal to applied force

the magnitude of static frictional force is 55 N

the crate will not move

the net force on the crate is zero

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1. A 12-kg wooden crate rests on the floor (which is horizontal), with the coeff

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1. A 12-kg wooden crate rests on the floor (which is horizontal), with the coeff

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