MASTER IT HINTS GETTING STARTED I CM STUCK Use the equations below. (Note that t

Question

MASTER IT HINTS GETTING STARTED I CM STUCK Use the equations below. (Note that the direction is indicated by the sign in front of the equations.) x = (0.0561)cos(3.881t + 0.15n) -(0.218)sin(3,881t+0.15) a =-(0.845)cos(3.881t + 0.15n) a) Determine the first time (greater than zero) that the position is at its maximum value. 81 x s Set the argument of the sine or cosine function to the value that satisfids the stated condition, and solve for the time. (b) Determine the first time (greater than zero) that the velocity is at its maximum value. 405 stated condition, and solve for the time. x s Set the argument of the sine or cosine function to the value that satisfies the

Explanation / Answer

a)

From

X=(0.0561)Cos(3.881t+0.15pi)

Here X=0.0561 for maximum value of position

=>0.0561=0.0561Cos(3.881t+0.15pi)

Cos-1(1)=3.881t+0.15pi

3.881t+0.15pi=2pi

t=1.4975 s

b)

Now V=-0.218 m

=>-0.218=-0.218sin(3.881t+0.15pi)

3.881t+0.15pi=sin-1(-1)=3pi/2

t=1.0928 s

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