Two identical, uniform and frictionless spheres, cach of massm, rest in a rigid

Question

Two identical, uniform and frictionless spheres, cach of massm, rest in a rigid rectangular container as shown in the figure. A line connecting their centers is at 15e to the horizontal. in each of the following cases find the magnitude of the force in terms of a ratio to the weight (mg). For example, if one of the forces is 1.5 times the weight, enter '1.5' without any units. What is the magnitude of the force on the spheres from the left side of the containar? | Submit Answer Incorrect. Trier 4, Previous Trides what is the magnitude of the force on the spheres from the right side of the container? | Submit Answer Incorrect. Trier 1/10 Previous Tris What is the magnitude of the force on the spheres from the bottom of the container? | Submit Answer this question expects a numeric answer. Tries o/10 Previous Trica What is the magnitude of the force that time top sphere exerts on the bottom sulhere? |Submit Answer Tries of 10 If the angle is increased to go think about what happens to the forces. This can help provide a chack to your answers as we make a change to the problem. For all of the following questions, the configuration is now changed such that the line connecting their centers is at an angle 24,4° to the horizontal At this new angle, what is the magnitude of the force on the spheres from the left side of the container? |Submit Answer Trias 0/10 What is the magnitude of the force on the spheres from the right side of the container? Submit Answer Tries o/10 What is the magnitude of the force on the spheres from the bottom of the container? |Submit Answer Tries 0/10 what is the magnitude of the force of the top sphere on the bottom sphere? | Submit Answer Tries of 10

Explanation / Answer

the contact force exerted by the lower sphere on the upper os along that is 45 and the force exerted by the wall a and floors are normal

equilibrium force on the top sphere leads to

Fwall=Fcos45 and Fsin45=mg

sphere leads to

F wall=Fcos45 and F floor=Fsin45+mg

A)magnitude of the forces on the sphere from the left side

F wall=mg

B)magnitude of the force on the sphere from the right side

F wall =mg

C)magnitude of the forces on the sphere from the bottom

F floor=mg+mg=2mg

D)magnitude of the force on the sphere from each other

F=mg/sin45

=mg*root2.

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