1 out of 8 attempts Assi Ci Vi Vi Sh Gu Pr Pr Qu Re r final answer to three sign

Question

1 out of 8 attempts Assi Ci Vi Vi Sh Gu Pr Pr Qu Re r final answer to three significant figures. Find the force exerted by the biceps muscle in holding a 2.00-L milk carton (weight 19.8 N) with the forearm parallel to the floor. Assume that the hand is 37.6 cm from the elbow and that the upper arm is 27.4 cm long. The elbow is bent at a right angle and one tendon of the biceps is attached to the forearm at a position 5.00 cm from the elbow, while the other tendon is attached at 27.4 cm from the elbow. The weight of the forearm and empty hand is 21.7 N and the center of gravity of the forearm is at a distance of 17.8 cm from the elbow MILK 27.4 CG

Explanation / Answer

The Tension vector is from a point 5 cm to the right of the elbow to a point 27.4 cm above the elbow. These lengths are 2 sides of a right triangle.
The tangent of the angle between horizontal and the Tension vector = 27.4/5 = 5.48
The angle = Inverse tangent of 5.48 = 79.6584

I chose the elbow as the pivot point.
Torque caused by Tension vector = The vertical component of the Tension vector * horizontal distance between the elbow and point where the tendon is attached to the forearm.

Torque caused by Tension vector = T * sin 79.6584 * 0.05

Torque caused by weight of forearm = 21.7 * 0.178
Torque caused by weight of milk carton = 19.8 * 0.376

T * sin 79.6584 * 0.05 = 21.7 * 0.178 + 19.8 * 0.376
T = (21.7 * 0.178 + 19.8 * 0.376) ÷ (sin 79.6584 * 0.05)

T = 468.11 N

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