Magnetic Force II Begin Date: 11/6/2017 12:01:00 AM--Due Date: 11/12/2017 11:59:

Question

Magnetic Force II Begin Date: 11/6/2017 12:01:00 AM--Due Date: 11/12/2017 11:59:00 PM End Date: 11/30/2017 11:59:00 PM (1496) Problem 3: A proton moves in a circular path of the same radius as a cosmic ray electron moving at 7.5 × 106 ms perpendicular to the Earth's magnetic field at an altitude where the field strength is 1.0 10 ×Incorrect Answer The provided answer is not correct and no specific feedback is available Please view available hints and review the relevant material. > 25% Part (a) What will the speed of the proton be in ms? 11.3171 Grade Summary 12% 8890 Potential sin0 tan() | (! 7 8 9 HOAME co eted eted cotan0 asinO acos0 atan acotan0sinh0 cosh0 tanh0cotanhO Submissions Attempts remaining: 17 (4% per attempt) detailed view END eted eted 490 490 4% Degrees O Radians BACKSPACE DEL CLEAR Submit Hint I give up! eted Hints: 090 deduction per hint. Hints remaining:j3 Feedback: 0% deduction per feedback. /2 2590 Part (b) What would the radius of the path be in meters if the proton had the same speed as the electron? 2596 Part (c) what would the radius be in meters if the proton had the same kinetic energy as the electron? 25% Part (d) What would the radius be in meters if the proton had the same momentum as the electron?

Explanation / Answer

(a)

radius when a particle moving in a circular path in uniform magnetic field,

r = mv / qB

rp = me*ve / qB

re = me*ve / qB

re / rp = me*ve / mp*vp

as given that, re = rp

vp = me*ve / mp

vp = 9.1*10^(-31)*7.5*10^6 / 1.67*10^(-27)

vp = 4.08*10^3 m/s

(b)

if, ve = vp

re / rp = me*v / mp*v

rp = mp*re / me

re = me*ve / qB = (9.1*10^(-31)*7.5*10^6 / 1.6*10^(-19)*1*10^(-5))

re = 4.265 m

rp = (mp / me) * re

rp = (9.1*10^(-31) / 1.67*10^(-27)) * 4.265

rp = 7.83*10^3 m

(c)

if, KEe = KEp

r = sqrt (2mK) / qB

re / rp = sqrt (me / mp)

rp = sqrt (mp / me) * re

rp = sqrt ((9.1*10^(-31) / 1.67*10^(-27)) * 4.265

rp = 182.74 m

(d)

if, Pe = Pp

r = P / qB

then, re = rp

rp = 4.265 m

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