Magnesium hydroxide is only very slightly soluble in water. The reaction by whic

Question

Magnesium hydroxide is only very slightly soluble in water. The reaction by which it goes into solution is: Mg(OH)2 (s) <=> Mg2+ (aq) + 2 OH- (aq) Explain why Mg(OH)2 might have very appreciable solubility in 1M HCl. ( Consider the effort of Reaction 3 on the Mg(OH)2 solution reaction.) Magnesium hydroxide is only very slightly soluble in water. The reaction by which it goes into solution is: Mg(OH)2 (s) <=> Mg2+ (aq) + 2 OH- (aq) Explain why Mg(OH)2 might have very appreciable solubility in 1M HCl. ( Consider the effort of Reaction 3 on the Mg(OH)2 solution reaction.) Explain why Mg(OH)2 might have very appreciable solubility in 1M HCl. ( Consider the effort of Reaction 3 on the Mg(OH)2 solution reaction.)

Explanation / Answer

Mg(OH)2 (s) <=> Mg2+ (aq) + 2 OH- (aq)

Ksp for the above equation is x 10^-13, i.e, the it is not highly soluble. In order to dissolve significant amount of Mg(OH)2 you should increase the concentration of  Mg2 and OH-.

In case of HCl it dissociate as H+ and Cl-. The H+ of acid will react with the OH- from Mg(OH)2. According to Le Chatlier,s principle if you remove OH- from the equilibrium, the equilibrium will shift to right hand side and more Mg2+ will move into the solution and one more thing here you are dealing with solubility of MgCl2 which have a higher Ksp value than Mg(OH)2. Hene Mg(OH)2 have appreciable solubility in 1M HCl.

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