Item 8 Part A A 96.0 nF capacitor is charged to 14.0 V, then disconnected from t
ID: 1781031 • Letter: I
Question
Item 8 Part A A 96.0 nF capacitor is charged to 14.0 V, then disconnected from the power supply and connected in series with a coil that has At an instant when the charge on the capacitor is 0.720 C , what is the magnitude of the current in the inductor? 3.70x10-2 H and negligible resistance Express your answer with the appropriate units |=| Value Units Submit swers Give Up Incorrect, Iry Again, 28 attempts remaining Part B At an instant when the charge on the capacitor is 0.650 change of this current? , what is the magnitude of the rate of di dt Submit My Answers Give Up ovide Feedback ContinueExplanation / Answer
total initial energy Ei = (1/2)*C*V^2
energy at any instant Ef = (1/2)*q^2/C + (1/2)*L*I^2
total energy remains constant
Ef = Ei
(1/2)*(0.72*10^-6)^2/(96*10^-9) + (1/2)*2*10^-2*I^2 = (1/2)*96*10^-9*14^2
current I = 0.026 A <<<<<--------ANSWER
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part B
VL = V - q/C
L*di/dt = V - q/C
2*10^-2*di/dt = 14 - 0.65*10^-6/(96*10^-9)
rate of current di/dt = 361.5 A/s
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