e Edit View History Bookmarks People Window Help Responses/submit\'?dep 16724930

Question

e Edit View History Bookmarks People Window Help Responses/submit'?dep 16724930 A group of students, performing the same "Uniform Circular Motion Oircular Motion" experiment that you performed in lab, obtained the following results. 0.2430 0.096s 81 006625 87.3 1 0.2610 0.105580 0.2980 0 0.3425 0.14625 80.3 For this table, r is the distance from the center of rotation to the mn is the total hanging mass (including the hanger), and t is the time required for 50 complete rotations t radlus Indicator (0e., the post that marks the position of the center of the bob dur (a) Use Excel to e construct a spreadsheet that show the following. (You will not submit this spreadsheet. However, the results will be needed 0) the above data u) all caloulations needed to compute the acceleration, a, for each trialTJ i) a graph of mg v acT (v) Use the trendine option to draw the best fit line and determine its slope. (b) Report this value below. Unform Cinoular Motion Pro MacBook 3 4 K.

Explanation / Answer

All we can help with in this forum is

(ii) acceleration a = v^2 / r

v = 50*2pi*r / t

so a = 10000*pi^2*r^2 / (*t^2*r)

a = 10000pi^2*r / t^2

a = 98696*r / t^2

e.g. for the first trial

a = 98696*0.1825 m / (87.39s)^2 = 2.36 m/s^2

for the second trial

a = 98696*0.2430 m / (81.16s)^2 = 3.64 m/s^2

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