Forces HW 4 Google Chome Secure : https://session masteringphysics.com/m yc t/it
ID: 1780563 • Letter: F
Question
Forces HW 4 Google Chome Secure : https://session masteringphysics.com/m yc t/itemView offsenext&assignmentProblemi; D-8 1 4653 Ba Forces Hw4 Problem 2 71 a prevlous i 28 of 28 l retum to assi Problem 2.71 Part A A stone is thrown vertically upward wih a speed of 17.3 my's from the edge of a cill 750 m high lEigure.11 How much later does it reach the botom of he d? Express your answer to three significant figures and include the appropriate units. My Answers Glve Up Wha: is its speod just batoo hiting Express your answer to three significant figures and include the appropriate units iA Vale m/s My Answers Gve Up Part C What total cstancu id it va Express your answer to three significant figures and inclade the appropriate unts 3 ? My Answers gto upExplanation / Answer
(a)
Let:
y0 be initial height,
u be initial speed up,
g be acceleration due to gravity,
t be time.
0 = y0 + ut - gt^2 / 2
0 = 75.0 + 17.3t - 9.81t^2 / 2
9.81t^2 / 2 - 17.3t - 75.0 = 0
The positive root is:
t = (17.3 + sqrt(299.29 + 2 * 9.81 * 75)) / 9.81
= 6.05 sec.
(b)
Let v be final speed.
v = u - gt
= 17.3 - 9.81 * 6.05
= - 42.1 m/s.
That's 42.1 m/s downwards.
(c)
Let y be height reached above the cliff.
0 = u^2 - 2gy
y = u^2 / 2g
= 17.3^2 / (2 * 9.81)
= 15.3 m.
The total distance is:
2y + 75.0
= 106 m.
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.