A 3000-m-high mountain is located on the equator. How much faster does a climber

Question

A 3000-m-high mountain is located on the equator.

How much faster does a climber on top of the mountain move than a surfer at a nearby beach? The earth's radius is 6400 km.

Please use the numbers that are provided in the question so that I can see what I am doing incorrectly. Thank you very much in advance.

Problem 4.30 Part A A 3000-m-high mountain is located on the equator. How much faster does a climber on top of the mountain move than a surfer at a nearby beach? The earth's radius is 6400 km. Express your answer to two significant figures and include the appropriate units. IA Au= V Units atue Submit My Answers Give Up Continue

Explanation / Answer

The angualr momentum speed(w) is the same,the linear speed(v)

V1=2(pi)r/t=>v=2(3.14)(6.4*10^6)/86400=465.18m/s (speed on the beach).

V2=2*3.14(6.4*10^6+3.0*10^3)/86400=465.40m/s (speed on the mountain top)

the speed difference=465.18-465.40

=0.22m/s

AND 86400 IS THE NUMBER OF SECONDS IN ONE DAY (24*60*60).

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.