Three blocks of masses 3m, 2m, ands are connected to strings A, B, and C as show
ID: 1780525 • Letter: T
Question
Explanation / Answer
mAa = Ta - umAg
mBa = TB - TA - umBg
mAa = F - TB - umCg
F = (mA + mB + mC)a = 6ma
then
a = F/(6m)
TA = mAa + umAg = 1/2F + 3umg
TB = Ta + mBa + umBg = 1/2F + 3umg + 1/3F + 2umg = 5/6F
TC = F = TB + mAa + umAg = 5/6F + 5umg + F/6 + umg = F + 6u
then
TC > TB > TA
the correct answer is C
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