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Three blocks of masses m_1 = 1.4 kg, m_2 = 1.9 kg, and m_3 = 5.5 kg are connecte

ID: 1529905 • Letter: T

Question

Three blocks of masses m_1 = 1.4 kg, m_2 = 1.9 kg, and m_3 = 5.5 kg are connected b massless strings, one of which passes over a frictionless pulley of negligible mass, as to the left. each of the following: acceleration of the 5.5 kg block. _________ m/s^2 tension in the string supporting the 5.5 kg block. __________ N tension in the string connected to the 1.4 kg block. ___________ N bodied frictionless hand exerts a horizontal force against a block weighing 14.0 N (weight is rot mass!). T with a vertical wall. of static friction between the wall and the block is 0.67, and the coefficient of kinetic friction is 0.47. the finger exerts no friction against the block. the minimum amount of normal force F that the wall must exert against the block so that the the block __________ N of force does the finger exert against the block? _________ N the minimum amount of horizontal force F necessary for the block to slide down the wall with a constant _________ N of force does the finger exert against the block now? _______ N exerts a force of 30 N against the block. What amount of friction force does the wall exert against the block ____________ N

Explanation / Answer

let a be the acceleration of the mass m3 then the equation of motion

m3a = m3g -m1g-m2g

a = g (m3-m1-m2) /m3 = 9.8*(5.5-1.4-1.9)/5.5 = 3.92 m/s2

b) suppose T is the tenstion in the string supporting m3 then the equation of motion

m3a = m3g -T

T = m3(g-a)   = 5.5(9.8-3.92) = 32.34 N

acceleration of all masses m1,m2,m3 will be same as all of them ae connected with string

suppose T1 is the tension in string supporting m1 then

m1a = T1 - m1g =

T1 = m1(g+a) = 1.4*(9.8+3.92) = 19.21 N

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