(8%) Problem 10: A rod of mass M = 128 g and length L = 49 cm can rotate about a
ID: 1780480 • Letter: #
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(8%) Problem 10: A rod of mass M = 128 g and length L = 49 cm can rotate about a hinge at its left end and is initially at rest. A putty ball of mass m1 = 11 g, moving with speed V= 10 m/s, strikes the rod at angle = 20° a distance D-Li4 from the end and sticks to the rod after the collision ©theexpertta.com 33% Part (a) what is the total moment of inertia, 1, with respect to the hinge, of the rod-ball-system after the collision? 33% Part (b) What is the angular speed of the system immediately after the collision, in terms of system parameters and moment of inertia r! × 33% Part (c) Calculate the rotational kinetic energy of the system after the collision, in J rot0.0281 Grade Summary Deductions Potential 8% 92% 7 89HOME Submissions Attempts remaining: 3 (4% per attempt) detailed view tan() | | ( cosO cotan0 asin) acos0 atan)acotan) sinh0 cosh0 tanh0 cotanh0 °Degrees Radians 4% 4% 0 END O BACKSPACE DEL CLEAR Submit Hint I give up! Hints: 2% deduction per hint. Hints remaining: 2 Feedback: 2% deduction per feedbackExplanation / Answer
c] By angular momentum conservation, i w = mv L cos theta
(ML^2/3 + mD^2) w = mvL cos 26 degree
w*(0.128*0.49^2/3+0.011*(0.49/4)^2) = 0.011*10*0.49* cos 26 degree
w*0.010409 = 0.04844
w = 0.04844/0.010409 = 4.654 rad/s
Trot = 0.5 i w^2
= 0.5*(0.128*0.49^2/3+0.011*(0.49/4)^2)*4.654^2
= 0.1127 J answer
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