OPTICAL IMAGING 1: Consider a mixture of two chromophores A and B that have exti

Question

OPTICAL IMAGING 1: Consider a mixture of two chromophores A and B that have extinction coefficients a (h)-2.5×104 M-1cm", a (h)-82-104 M-1cm", B (h)-6.3x105 M-1cm", a.) = 1.4x 105 M-1cm-1 at two wavelengths | and 2 . The absorption coefficients of the . at the two wavelengths are .(A, ) = 1.8 cm" and .(.) = 3.1 cm-1 (a) What are the concentrations of chromophores A and B in the mixture? (b) What are the changes in the absorption coefficient of the mixture at the two wavelengths if the concentration of chromophore A is doubled and that of chromophore B is tripled? OPTICAL IMAGING 2: Air n= 1.0 Fiber Core n = 1.53 Fiber face Fiber x fiber 0.0025 inch in diameter has a core index of 1.53 and a cladding index of 1.39. See drawing d fibers are used frequently in applications involving communication, sensing, and imaging. What is the A step-inde Such cla maximum acceptance a core of the fiber is incident on the cladding at the critical angle? ngle for a cone of light rays incident on the fiber face such that the refracted ray in the

Explanation / Answer

2.

let the maximum acceptance angle be thetam

then

given

core refractive index, n1 = 1.53

cladding refractive index, n2 = 1.39

then

from snells law

sin(thetam)/sin(thetaf) = n1

also for total internal reflection limit

sin(thetac)/sin(90) = n2/n1

but thetac = 90 - thetaf

cos(thetaf) = n2/n1 = 1.39/1.53 = 0.9084

thetaf = 24.701 deg

hence

sin(thetam) = 1.53*sin(thetaf)

thetam = 39.744 deg

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