Number 17 please vertically downward, and in 25 ms it increases linearly from 5.

Question

Number 17 please

vertically downward, and in 25 ms it increases linearly from 5.0 mt to 55 mTFind the magnetic flux through the loop at (a) the beginning and (b) the end of the 25-ms period. (c) What's the loop current during this time? (d) Which way does this current flow? 17. A conducting loop of area 240 cm and resistance 12 N is perpen dicular to a spatially uniform magnetic field and carries a 320-mA induced current. At what rate is the magnetic field changing? 18. The magnetic field inside a 23-cm-diameter solenoid is increasing at 2.4 TIs. How many turns should a coil wrapped around the outside of the solenoid have so that the emf induced in the coil is 15 V? Section 27.4 Inductance 19. Find the selfinductance of a 1500-turn solenoid 55 cm long and 4.0 cm in diameter 20. The current in an inductor is changing at 110 A/s and the indue tor emf is 45 V. What's the self-inductance? 21. A 19-A current is flowing in a 22-H inductor. A switch opens, inter rupting current in 10 msinduced emf in the inductor. the . Find the tah D1 11 for

Explanation / Answer

Lenz's law gives the induced voltage in a conductor due to a changing magnetic flux. Let B = magnetic field strength, A = area of conductor, t = time, V = induced voltage.

So Lenz's law is given by

V = -d(BA)/dt where here BA assumes the magnetic field is perpendicular to the surface of the conductor

Given:A =240 cm^2 = 0.024 m^2

Here A is independent of time so,

V=-A dB/dt

dB/dt = -V/A

By using Ohm's Law
V=IR where I = current in the circuit and R = resistance in the circuit.
So, by equating both we get
dB/dt = -IR/A

Given: I = 0.32 A and R = 12 Ohms and A = 0.024 m^2

dB/dt=-0.32*12/.024=160 Tesla/sec

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.