7. +-12 points SerCP11 3.P.015 My Notes Ask Your Teacher A car is parked on a cl

Question

7. +-12 points SerCP11 3.P.015 My Notes Ask Your Teacher A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 20.0° below the horizontal. The negligent driver leaves the car in neutral, and the emergency brakes are defective. The car rolls from rest down the incline with a constant acceleration of 3.21 m/s for a distance of 60.0 m to the edge of the cliff, which is 25.0 m above the ocean (a) Find the car's position relative to the base of the cliff when the car lands in the ocean. b) Find the length of time the car is in the air. Need Help? Read It

Explanation / Answer

let's find the velocity at the base of cliff for car

v^ 2= 2 (a)(x)

v = sqroot ( 2ax) = sqroot (2 x3.21x60) = 19.626 m/s

at this pint, the car wil fall

Vx= 19.626 ( cos20)= 18.44 m/s

Vy ( initial vertical velcity) = 19.626 sin 20 =6.712 m/s apprx

time of fall

25= 6.712 (t) + 1/2 (9.8) t^2

4.9t^2 + 6.712 t - 25=0

t=- 6.712 +- 23.13/ 9.8 = 1.675 seconds apprx---------time when the call is in air

position of car relative to base of cliff= 18.44 m/s (1.675) = 30.89 m apprx

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