7. +-10 points TiplerS 27,PO81.soln. My Notes A long, straight wire carries a cu

Question

7. +-10 points TiplerS 27,PO81.soln. My Notes A long, straight wire carries a current of 11-15.4 A as shown in the figure. A rectangular coil with two sides parallel to the straight wire has sides 5 from the wire. The coil carries a current of 12 = 6.33 A. and 10 cm with the near side a distance 2 cm 5 cm- 10 cr 2 cm (a) Find the force on each segment of the rectangular coil due to the current in the long, straight wire. top segment left segment bottom segment right segment NDirection NG-Direction ! N -Direction- (b) What is the net force on the coil? NDirection- eBook

Explanation / Answer

Given, I1=15.4 A I2=6.33 A

The magnetic field due to Long wire carrying current I1 is µ0I1/2d , where d is the distance at which the value of B is needed

Force on any segement is µ0I1I2/2d d is the distance between I1 and I2

a)

TOP SEGMENT

F1= µ0I1I2/2*ln(7/2) upwards

F1= 1.556*10-5 N upwards

LEFT SEGMENT

F2= µ0I1I2/2d {d=0.02 m}

F2= 9.7482*10-4 N Right hand side

BOTTOM SEGMENT

Same as part a) but in the opposite direction

F3= 1.556*10-5 N downwards

RIGHT SEGMENT

F4= µ0I1I2/2d {d=0.07 m}

F4= 2.7852*10-4 N Left hand side

b)

Force on top and bottom will cancel each other out because they are equal and opposite

net force=F2 -F4 = (9.7482*10-4 - 2.7852*10-4) Right hand side

= 6.963*10-4 N on the Righthand side

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