1, Two conducting spheres are concentrically nested as shown in the cross-sectio
ID: 1778700 • Letter: 1
Question
1, Two conducting spheres are concentrically nested as shown in the cross-sectional diagram below. The inner sphere has a radius of 3 cm and a net charge of 2BM .C. The outer spherical shell has an inner radius of 6 cm, an outer radius of 8 cm, and a net charge ofisBD 10 a) Determine the net charge on the inner surface of the outer spherical shel b) Determine the net charge on the outer surface of the outer spherical shell c) What is the expression for the Electric field for r between 0 and 3 em? d) What is the expression for the Electric field for r between 3 and 6 cm? e) What is the expression for the Electric field for r beyond 6 em? What is the expression for the Electric potental for r between 0 and 3 cm? g) What is the expression for the Electric potential for r between 3 and 6 cm? h) 2. What is the expression for the Electric potential for r beyond 6 cm? 2. Repeat a) through h) if a point charge of BM is now added and glued at the center of the inner sphere. 3. If each block in the diagram below represents a capacitor Farads), using the concept of equivalent capacitance, find the charge on each plate of the capacitors, the potential difference across each capacitor, and place a +on the side of the capacitor indicating the higher potential 10v BD BD 4. . Ifeach block in the above diagram represents a resistor (Ohms), using the concept of equivalent resistance, find the current through each resistor, the potential difference across each resistor, and place aon the side of the resistor indicating the higher potential side.Explanation / Answer
Problem 1)
a) 12 C of charge on the inner surface
b) +15 C of charge on the outer surface
c) For the first 3 cm the Gaussian sphere contains no charge, which means there is no electric field. That's the way it works in a conductor. There can be no field inside a conductor once the charges find their equilibrium distribution.
Therefore, E = 0 V/m for r = 0 to 3 cm
d) When the radius reaches 3 cm the Gaussian sphere finally contains some charge i.e. Qnet = +12 C
Electric field, E = k Q/ r2 = (9 X 109 x 12 x 10-6)/ r2 = (108000 Vm / r2) for 3 cm to 6 cm
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