Use the exact values you enter in previous answer(s) to make later calculation(s
ID: 1776692 • Letter: U
Question
Use the exact values you enter in previous answer(s) to make later calculation(s). A 1130 kg car traveling intally with a sped of 26.40 m/s in an easterly direction crashes into the back of a 9 aso k truck moving in the same drection at The velocity of the car right after the collision is 18.0 m/s to the east. k moving in the same direction at 20.0 m/s. Before After (a) What is the velocity of the truck right after the collision? (Give your answer to at least four significant figures.) magnitude direction m/s b) What is the change in mechanical energy of the car-truck system in the collision?Explanation / Answer
Here,
a) let the velocity of the truck after the collision is v
Using conservation of momentum
1130 * 26.40 + 9490 * 20 = 1130 * 18 + 9490 * v
v = 21 m/s
the velocity of the truck is 21 m/s to the east
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change in mechanical energy = -(0.50* 1130 * 26.40^2 + 0.50 *9490 * 20^2 - 0.50 * 1130 * 18^2 + 0.50 * 9490 * 21^2)
change in mechanical energy = -4201267.4 J
the change in mechanical energy is -4201267.4 J
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