The f The insert has a dielectric constant of e30. The uniform fleld between the

Question

The f The insert has a dielectric constant of e30. The uniform fleld between the plates is shown as red arrows and its magwitude in the ARSENCE of the dielectric is 15x 10 (a) What is magsitude of the electric field between the plates. in the presence of the dielectric Please explain your answer (e) Which plate, upper or lower, is at a higher potential relative to the other (b) Which plate, upper or lower, is positvely char ged and which negatively charged Please explain your answer (d) Explain in words why the value of the electric field changes

Explanation / Answer

(A) E = 1 x 10^5 N/C

E' = E/k = 3333.3 N/C

(B) field is from +ve to -ve plate.

upper plate -> -ve charges

lower plate -> +ve charged

(C) lower plate is at higher potential.

(d) as dielectric inserted, due to ion of dielectric a field is generated in opposite direction.

so field strength will be decreased.

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