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The figure shows an overhead view of a 2.80-kg plastic rod of length 1.20 m on a

ID: 1776144 • Letter: T

Question

The figure shows an overhead view of a 2.80-kg plastic rod of length 1.20 m on a table. One end of the rod is attached to the table, and the rod is free to pivot about this point without friction. A disk of mass 57.0 g slides toward the opposite end of the rod with an initial velocity of 30.5 m/s. The disk strikes the rod and sticks to it. After the collision, the rod rotates about the pivot point. disk pivot (a) What is the angular velocity of the two after the collision? 1.41 What is the angular momentum of an object moving with a linear velocity, about a given point? rad/s (b) What is the kinetic energy before and after the collision? KE, 22 34 nitially the disk has translational motion while after collision the disk and stick have rotational motion. KEf =

Explanation / Answer

a)

By Conservation of angular momentum

Li = Lf

mvL =[(1/3)ML2+mL2]*W

(57*10-3)*30.5*1.2 = [(1/3)*2.8*1.22+0.057*1.22]*W

W=1.463 rad/sec

b)

Initial Kinetic energy

KEi=(1/2)mV2=(1/2)*0.057*30.52=26.51 J

Final Kinetic energy

KEf=(1/2)IW2=(1/2)[(1/3)*2.8*1.22+0.057*1.22]*1.4632=1.526 J

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